document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=50782>Question 50782</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0073016020/algebrahomeworkh>Beginning Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Can someone please help me. I am not sure what my practice problem is asking me to do.\r<BR>\n" );
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document.write( "Graph using the intercept method: x + 3y = 6<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #33813 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=33813\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+3y=6 or puting this equation in the normal line format (y=mx+b) we get <BR>\n" );
document.write( "3y=-x-6 or y=-x/3-2 thus you have a line with a slope (m) of -1/3 & a y intercept (b) of -2 you now have one point (0,-2) now set y=0 we get 0=-x/3-2 or -x/3=2 or x/3=-2 or x=-6 now we have a second point(-6,0)<BR>\n" );
document.write( "plot these two points, draw a line through them and you have a line with a slope of -1/3 with a y intercept of -2 </SPAN>\n" );
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