document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=500267>Question 500267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the value of x if x + 60 is supplementary to x + 10? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338129 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338129\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> what is the value of x if x + 60 is supplementary to x + 10?<BR>\n" );
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document.write( "Two angles that are supplementary, add up to 180, therefore<BR>\n" );
document.write( "(x+60) + (x+10) = 180<BR>\n" );
document.write( "2x + 70 = 180<BR>\n" );
document.write( "2x = 180 - 70<BR>\n" );
document.write( "2x = 110<BR>\n" );
document.write( "x = 110/2<BR>\n" );
document.write( "x = 55 </SPAN>\n" );
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