document.write( "Question 499756: write an equation that passes through the given point and satisfies the given condition.
\n" ); document.write( "(7,1);parallel to y=-x+3 \n" ); document.write( "
Algebra.Com's Answer #338096 by Flannery(124)\"\" \"About 
You can put this solution on YOUR website!
Ok, first y=-x+3 is in \"point-slope\" form.
\n" ); document.write( "The format for it is y=bx+c.
\n" ); document.write( "The y intercept is the place where y is 3 and x is 0 in this one.
\n" ); document.write( "I'll show you.
\n" ); document.write( "Find values for x when y = {0,1,2,3,}
\n" ); document.write( "0=-x+3
\n" ); document.write( "x=3
\n" ); document.write( "(3,0) meaning (x value, y value)
\n" ); document.write( "The \"c\" term in \"point-slope\" tells you the value for x when y=0. In this case 3
\n" ); document.write( "now a few more points on the line \"y=-x+3\"
\n" ); document.write( "1=-x+3
\n" ); document.write( "x=2
\n" ); document.write( "(2,3)
\n" ); document.write( "2=-x+3
\n" ); document.write( "x=1
\n" ); document.write( "(2,1)
\n" ); document.write( "3=-x+3
\n" ); document.write( "x=0
\n" ); document.write( "(3,0)
\n" ); document.write( "Plot this on graph paper and its a line passing through the y axis at (0,3) and the x axis at (3,0).
\n" ); document.write( "Now to get a parallel.
\n" ); document.write( "remember the formula for your equation, y=-x+3
\n" ); document.write( "you'll need to \"just know\" that the \"c\" term, in this case 3, is always the x value when y=0
\n" ); document.write( "you'll need to \"just know\" that the \"b\" term, or the coefficient of x is always the slope. In this case the slope is -1.
\n" ); document.write( "Slope is rise over run, or the ratio of increase in y over increase in x.
\n" ); document.write( "In this case -1 over 1.
\n" ); document.write( "So start at (7,1) and start plotting a line with a slope of -1.
\n" ); document.write( "The first thing you should come to is the x intercept at (0,8).
\n" ); document.write( "Because increase in y is -1 (go down a square) and increase in x is one (go right a square).
\n" ); document.write( "Now to plot some more of the second line by useing \"point slope\".
\n" ); document.write( "Negative slopes like this one always slant downward from left to right, and if we keep going down we next hit (9,-1).
\n" ); document.write( "What if we backed up? to do so reverse the direction and go up a y value back an x value. we can back up to(6,2),(5,3),(4,4),(3,5),(2,6)(1,7)(0,8) and so on.
\n" ); document.write( "If you want to check all this work, there are solvers on the site. My guess is your class already requires you to have a graphing calculator. (I checked this with Microsoft Mathematics, which is a free download).
\n" ); document.write( "Anyway this way of getting what you are looking for is the by hand graphing method aka \"ol' plug n chug\"
\n" ); document.write( "Now that we found the y intercept at (0,8) we know enough to write a new equation, y=-x+8
\n" ); document.write( "y=-x+8 passes through (7,1) and is paralell to y=-x+3\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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