document.write( "Question 500265: How many liters of 15% acid solution must be added to a 120 liters of 35% acid solution to obtain a solution that is 22%. (use Fraction for answer) \n" ); document.write( "
Algebra.Com's Answer #338093 by mananth(16946)![]() ![]() You can put this solution on YOUR website! percent ---------------- quantity \n" ); document.write( "Acid solution I 35 ---------------- 120 liters \n" ); document.write( "Acid solution II 15 ---------------- x liters \n" ); document.write( "Mixture 22 ---------------- 120 + x liters \n" ); document.write( " \n" ); document.write( "35 * 120 + 15 x = 22 ( 120 + x ) \n" ); document.write( "4200 + 15 x = 2640 + 22 x \n" ); document.write( "15 x + -22 x = 2640 - -4200 \n" ); document.write( "-7 x = -1560 \n" ); document.write( "/ -7 \n" ); document.write( "x = 222 6/7 \n" ); document.write( " 222 6/7 liters of 15 % Acid solution II \n" ); document.write( " \n" ); document.write( " |