document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=500268>Question 500268</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if a bus travels 300km at a given speed. if the speed is increased to 10 kph the trip would have been reduced by one hour.find the speed of the bus. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338091 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338091\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the speed of the bus be x<BR>\n" );
document.write( "increased by 10 <BR>\n" );
document.write( "so speed = x+10\r<BR>\n" );
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document.write( "time with original speed - time with new speed = 1\r<BR>\n" );
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document.write( "300/x-300/(x+10)=1\r<BR>\n" );
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document.write( "LCD = x(x+10)\r<BR>\n" );
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document.write( "300*(x+10)-300x=x(x+10)<BR>\n" );
document.write( "300x+3000-300x=x^2+10x<BR>\n" );
document.write( "x^2+10x-3000=0<BR>\n" );
document.write( "x^2+60x-50x-3000=0<BR>\n" );
document.write( "x(x+60)-50(x+60)=0<BR>\n" );
document.write( "(x-50)(x+60)=0<BR>\n" );
document.write( "x=50 which is positive, the speed of the bus<BR>\n" );
document.write( " </SPAN>\n" );
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