document.write( "Question 499644: Solve by the elimination method 5r-2s=0 2r+5s=29 \n" ); document.write( "
Algebra.Com's Answer #338074 by Flannery(124)\"\" \"About 
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equation 1: 5r-2s=0
\n" ); document.write( "equation 2: 2r+5s=29
\n" ); document.write( "set your equations by multiplication so that one variable has opposite coefficients.
\n" ); document.write( "2(5r-2s=0)
\n" ); document.write( "-5(2r+5s=29)
\n" ); document.write( "now:
\n" ); document.write( "10r-4s=0
\n" ); document.write( "-10r-25s=-145
\n" ); document.write( "subtract equation 2 from equation 1 to eliminate the variable r.
\n" ); document.write( "-29s=-145
\n" ); document.write( "s=5
\n" ); document.write( "put the value of the variable you solved for into one of the origional equations and solve for the other variable.
\n" ); document.write( "5r-10=0
\n" ); document.write( "5r=10
\n" ); document.write( "r=2
\n" ); document.write( "check by putting both values you found into both equations.
\n" ); document.write( "5(2)-2(5)=0
\n" ); document.write( "10-10=0
\n" ); document.write( "0=0
\n" ); document.write( "2(2)+5(5)=29
\n" ); document.write( "4+25=29
\n" ); document.write( "29=29
\n" ); document.write( "Q.E.D.
\n" ); document.write( "
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