document.write( "Question 499644: Solve by the elimination method 5r-2s=0 2r+5s=29 \n" ); document.write( "
Algebra.Com's Answer #338074 by Flannery(124)![]() ![]() You can put this solution on YOUR website! equation 1: 5r-2s=0 \n" ); document.write( "equation 2: 2r+5s=29 \n" ); document.write( "set your equations by multiplication so that one variable has opposite coefficients. \n" ); document.write( "2(5r-2s=0) \n" ); document.write( "-5(2r+5s=29) \n" ); document.write( "now: \n" ); document.write( "10r-4s=0 \n" ); document.write( "-10r-25s=-145 \n" ); document.write( "subtract equation 2 from equation 1 to eliminate the variable r. \n" ); document.write( "-29s=-145 \n" ); document.write( "s=5 \n" ); document.write( "put the value of the variable you solved for into one of the origional equations and solve for the other variable. \n" ); document.write( "5r-10=0 \n" ); document.write( "5r=10 \n" ); document.write( "r=2 \n" ); document.write( "check by putting both values you found into both equations. \n" ); document.write( "5(2)-2(5)=0 \n" ); document.write( "10-10=0 \n" ); document.write( "0=0 \n" ); document.write( "2(2)+5(5)=29 \n" ); document.write( "4+25=29 \n" ); document.write( "29=29 \n" ); document.write( "Q.E.D. \n" ); document.write( " |