document.write( "Question 500215: Find two consecutive positive odd numbers such that sum of their squares is 74? \n" ); document.write( "
Algebra.Com's Answer #338073 by geetha_rama(94)\"\" \"About 
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Let X be a positive odd number.
\n" ); document.write( "Hence the next positive odd number = X+2 \r
\n" ); document.write( "\n" ); document.write( "X^2 + (X+2)^2 = 74\r
\n" ); document.write( "\n" ); document.write( "X^2 + X^2 + 4X + 4 = 74\r
\n" ); document.write( "\n" ); document.write( "2*X^2 + 4*X - 70 = 0\r
\n" ); document.write( "\n" ); document.write( "X^2 + 2*X - 35 = 0\r
\n" ); document.write( "\n" ); document.write( "X^2 + 7*X - 5*X - 35 = 0
\n" ); document.write( "X*(X+7) -5*(X+7)=0
\n" ); document.write( "(X+7)*(X-5)=0\r
\n" ); document.write( "\n" ); document.write( "Hence X= 5, -7
\n" ); document.write( "Since the number is a positive odd number ,
\n" ); document.write( "X = 5 and the next consecutive odd number is 7\r
\n" ); document.write( "\n" ); document.write( "Cross Check: 5^2 + 7^2 = 25 + 49 = 74
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