document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=498198>Question 498198</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a triangle is 45 inches. The first side is twice the length of the second, and the third is 5 inches longer than the second. Find the length of each side. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338065 by </B><A HREF=/tutors/aboutme.mpl?userid=Flannery><B>Flannery(124)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Flannery><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Flannery><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338065\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let 2S be side one<BR>\n" );
document.write( "Let S be side two<BR>\n" );
document.write( "Let S+5 be side three <BR>\n" );
document.write( "Perimeter equals 2S plus S plus S+5<BR>\n" );
document.write( "45=2S+S+S+5<BR>\n" );
document.write( "45=4S+5<BR>\n" );
document.write( "40=4S<BR>\n" );
document.write( "s=10<BR>\n" );
document.write( "45=2(10)+10+10+5<BR>\n" );
document.write( "45=20+10+10+5<BR>\n" );
document.write( "45=45<BR>\n" );
document.write( "Q.E.D.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );