document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=500224>Question 500224</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a diagonal of a rectangle is 60 cm long .if the length of the rectangle is 12 cm greater than the width .find the dimensions<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338064 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338064\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> width -------x<BR>\n" );
document.write( "length ---------x+12\r<BR>\n" );
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document.write( "diagonal --------60\r<BR>\n" );
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document.write( "They form a right triangle\r<BR>\n" );
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document.write( "x^2+(x+12)^2=60^2\r<BR>\n" );
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document.write( "x^2+x^2+24x+144=3600<BR>\n" );
document.write( "2x^2+24x-3456=0<BR>\n" );
document.write( "/2<BR>\n" );
document.write( "x^2+12x-1728=0<BR>\n" );
document.write( "x^2+48x-36x-1728=0<BR>\n" );
document.write( "x(x+48)-36(x+48)=0<BR>\n" );
document.write( "(x+48)(x-36)=0<BR>\n" );
document.write( "x=36 which is positive\r<BR>\n" );
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document.write( "36 & 48 are the sides </SPAN>\n" );
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