document.write( "Question 499791: a rectangular plot of land is to be used for a garden. 270 feet of fencing is to be used to enclos garden. what should demensions of garden be if length is twice as long as the width?
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document.write( "im not sure how to set up the equation to solve \n" );
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Algebra.Com's Answer #338058 by Flannery(124)![]() ![]() You can put this solution on YOUR website! Let P=perimeter \n" ); document.write( "Let L=length \n" ); document.write( "Let w=width \n" ); document.write( "Peremiter is 270 \n" ); document.write( "Twice length plus twice width is perimeter (P=2L+2W) \n" ); document.write( "Solve for W becouse we know L in terms of W \n" ); document.write( "P=4W+2W (because 2W = L for length and twice 2W is 4W) \n" ); document.write( "270=4W+2W \n" ); document.write( "270=6W \n" ); document.write( "W is 45 \n" ); document.write( "P is 2L plus 2W \n" ); document.write( "L is 2W \n" ); document.write( "2W is 90 \n" ); document.write( "Twice 90 plus twice 45 is twice the length plus twice the width. \n" ); document.write( "180 plus 90 is the perimiter. \n" ); document.write( "180 plus 90 is 270 \n" ); document.write( "Q.E.D. \n" ); document.write( " |