document.write( "Question 499791: a rectangular plot of land is to be used for a garden. 270 feet of fencing is to be used to enclos garden. what should demensions of garden be if length is twice as long as the width?
\n" ); document.write( "im not sure how to set up the equation to solve
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Algebra.Com's Answer #338058 by Flannery(124)\"\" \"About 
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Let P=perimeter
\n" ); document.write( "Let L=length
\n" ); document.write( "Let w=width
\n" ); document.write( "Peremiter is 270
\n" ); document.write( "Twice length plus twice width is perimeter (P=2L+2W)
\n" ); document.write( "Solve for W becouse we know L in terms of W
\n" ); document.write( "P=4W+2W (because 2W = L for length and twice 2W is 4W)
\n" ); document.write( "270=4W+2W
\n" ); document.write( "270=6W
\n" ); document.write( "W is 45
\n" ); document.write( "P is 2L plus 2W
\n" ); document.write( "L is 2W
\n" ); document.write( "2W is 90
\n" ); document.write( "Twice 90 plus twice 45 is twice the length plus twice the width.
\n" ); document.write( "180 plus 90 is the perimiter.
\n" ); document.write( "180 plus 90 is 270
\n" ); document.write( "Q.E.D.
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