document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=500135>Question 500135</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measurement of the second angle of a triangle is 21 degrees more than the measure of the first angle. The measure of the third angle is 15 degrees less than the measure of the first angle. Find the measure each angle of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338056 by </B><A HREF=/tutors/aboutme.mpl?userid=Flannery><B>Flannery(124)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Flannery><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Flannery><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338056\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let X be the measure of the first angle.<BR>\n" );
document.write( "X+21 is the measure of the second angle.<BR>\n" );
document.write( "X-15 is the measure of the third angle.<BR>\n" );
document.write( "180=X+X+21+X-15<BR>\n" );
document.write( "180=3X+6<BR>\n" );
document.write( "174=3X<BR>\n" );
document.write( "58=X<BR>\n" );
document.write( "58+(58+21)+(58-15)=<BR>\n" );
document.write( "58+79+43=<BR>\n" );
document.write( "180<BR>\n" );
document.write( "The measure of the first angle is 58.<BR>\n" );
document.write( "The measure of the second angle is 79.<BR>\n" );
document.write( "The measure of the third angle is 43.<BR>\n" );
document.write( "They add up to 180 degrees.<BR>\n" );
document.write( "Q.E.D. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );