document.write( "Question 499895: The measure of the supplement of an angle is 40 more than two times the measure of the complement of an angle. Find the measure of the angle. \n" ); document.write( "
Algebra.Com's Answer #338054 by Flannery(124)\"\" \"About 
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Let C stand for compliment.
\n" ); document.write( "Let S stand for suppliment.
\n" ); document.write( "Let A stand for angle.
\n" ); document.write( "A=90-C
\n" ); document.write( "S=A+2C+40
\n" ); document.write( "First solve for compliment.
\n" ); document.write( "180=90-C+2C+40
\n" ); document.write( "140=90-C+2C
\n" ); document.write( "140=90+C
\n" ); document.write( "50=C
\n" ); document.write( "90 degrees minus the compliment is the angle's measure.
\n" ); document.write( "90 minus 50 is 40.
\n" ); document.write( "40 degrees is the angle's measure.
\n" ); document.write( "Check by solving for suppliment.
\n" ); document.write( "S=2C+40
\n" ); document.write( "S=100+40
\n" ); document.write( "S=140
\n" ); document.write( "180 degrees minus the suppliment is the angle's measure.
\n" ); document.write( "180 minus 140 equals 40.
\n" ); document.write( "Fourty is the angle's measure.
\n" ); document.write( "Because 40+50=90 AND 40+2(50)+40=180
\n" ); document.write( "A=40
\n" ); document.write( "C=50
\n" ); document.write( "S=140
\n" ); document.write( "Q.E.D \n" ); document.write( "
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