document.write( "Question 500204: how many quarts of pure antifreeze must be added to 9 quarts of a 30% antifreeze solution obtain a 50% antifreeze solution \n" ); document.write( "
Algebra.Com's Answer #338048 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "Alcohol I 30 ---------------- 9 quarts
\n" ); document.write( "Alcohol II 100 ---------------- x quarts
\n" ); document.write( "Mixture 50 ---------------- 9 + x quarts
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\n" ); document.write( "30*9+100x=50(9+x)
\n" ); document.write( "270 + 100 x = 450 + 50 x
\n" ); document.write( "100 x + -50 x = 450 - -270
\n" ); document.write( "50 x = 180
\n" ); document.write( "/ 50
\n" ); document.write( "x = 3.6
\n" ); document.write( " 3.6 quarts of 100 % Alcohol II
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