document.write( "Question 500204: how many quarts of pure antifreeze must be added to 9 quarts of a 30% antifreeze solution obtain a 50% antifreeze solution \n" ); document.write( "
Algebra.Com's Answer #338048 by mananth(16946)![]() ![]() You can put this solution on YOUR website! percent ---------------- quantity \n" ); document.write( "Alcohol I 30 ---------------- 9 quarts \n" ); document.write( "Alcohol II 100 ---------------- x quarts \n" ); document.write( "Mixture 50 ---------------- 9 + x quarts \n" ); document.write( " \n" ); document.write( "30*9+100x=50(9+x) \n" ); document.write( "270 + 100 x = 450 + 50 x \n" ); document.write( "100 x + -50 x = 450 - -270 \n" ); document.write( "50 x = 180 \n" ); document.write( "/ 50 \n" ); document.write( "x = 3.6 \n" ); document.write( " 3.6 quarts of 100 % Alcohol II \n" ); document.write( " \n" ); document.write( " |