document.write( "Question 499515: Marie is 4 years younger than James, if the product of their ages 5 years ago is 45. What are their ages now?
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Algebra.Com's Answer #338040 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Present age of Marie = m
\n" ); document.write( "Present age of James = j\r
\n" ); document.write( "\n" ); document.write( "Marie is 4 years younger than James, means if we subtract 4 from James age both will be of equal age
\n" ); document.write( "m=j-4 .........(1)
\n" ); document.write( "5 years ago means we have to subtract 5 from their present ages
\n" ); document.write( "m-5=j-5
\n" ); document.write( "then
\n" ); document.write( "the product of their ages was 45
\n" ); document.write( "(m-5)*(j-5)=45
\n" ); document.write( "mj-5m-5j+25=45
\n" ); document.write( "mj-5m-5j=45-25
\n" ); document.write( "mj-5m-5j=20 ...........(2)
\n" ); document.write( "Put the value of m from (1) to (2)
\n" ); document.write( "(j-4)j-5(j-4)-5j=20
\n" ); document.write( "j^2-4j-5j+20-5j=20
\n" ); document.write( "j^2-14j+20=20
\n" ); document.write( "j^2-14j=20-20
\n" ); document.write( "j^2-14j=0
\n" ); document.write( "j(j-14)=0
\n" ); document.write( "Divide by j both sides of above equation
\n" ); document.write( "j(j-14)/j=0/j
\n" ); document.write( "j-14=0
\n" ); document.write( "j=14
\n" ); document.write( "Put the value of j in (1)
\n" ); document.write( "m=j-4 .........(1)
\n" ); document.write( "m=14-4
\n" ); document.write( "m=10
\n" ); document.write( "Present age of Marie = 10
\n" ); document.write( "Present age of James = 14\r
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