document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=499790>Question 499790</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a standard-sized rectangular rug is 28 ft. The length is 2 ft. longer than the width. find the dimensions </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #338037 by </B><A HREF=/tutors/aboutme.mpl?userid=Flannery><B>Flannery(124)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Flannery><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Flannery><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=338037\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimiter is two times width plus two times length.<BR>\n" );
document.write( "Width is x.<BR>\n" );
document.write( "Length is x+2<BR>\n" );
document.write( "28=2x+2(x+2)<BR>\n" );
document.write( "28=2x+2x+4<BR>\n" );
document.write( "28=4x+4<BR>\n" );
document.write( "24=4x<BR>\n" );
document.write( "24/4=6<BR>\n" );
document.write( "so x=6<BR>\n" );
document.write( "28=2(6)+2(6+2)<BR>\n" );
document.write( "28=12+12+2<BR>\n" );
document.write( "28=28<BR>\n" );
document.write( "Solution checks. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );