document.write( "Question 500171: A rectangular stained glass window has a perimeter of 42 feet. The height of the window is 2 times its width. Find the width of the window.\r
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document.write( "What am I suppose 2 do here. \n" );
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Algebra.Com's Answer #338033 by Flannery(124)![]() ![]() You can put this solution on YOUR website! Set width at w and height at 2w. \n" ); document.write( "The perimiter of a rectangle is twice the length times twice the hight. \n" ); document.write( "Twice the width is 2w. \n" ); document.write( "Twice the hight is 4w. \n" ); document.write( "Add them. The perimiter is 6w=42. \n" ); document.write( "42 divided by 6 is 7. \n" ); document.write( "The width is 7 feet. \n" ); document.write( "Are two widths of seven plus two lenghts of two sevens (14) 42? \n" ); document.write( "That's two 14 foot lengths and two 7 foot lenghts. \n" ); document.write( "Two 14s is 28. \n" ); document.write( "Two sevens is another 14. \n" ); document.write( "28 plus 14 is 42. \n" ); document.write( "Solution checks. \n" ); document.write( " \n" ); document.write( " |