document.write( "Question 500172: Find an equation of the line that satisfies the given conditions.
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document.write( "Through
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document.write( "(−8, −8);
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document.write( " perpendicular to the line passing through
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document.write( "(−5, 4) and (−1, 2)
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Algebra.Com's Answer #338031 by mananth(16946)![]() ![]() You can put this solution on YOUR website! x1 y1 x2 y2 \n" ); document.write( "-5 4 -1 2 \n" ); document.write( "We find the equation of this line \n" ); document.write( "slope m = (y2-y1)/(x2-x1) \n" ); document.write( "( 2 - 4 )/( -1 - -5 ) \n" ); document.write( "( -2 / 4 ) \n" ); document.write( "m= - 1/ 2 \n" ); document.write( " \n" ); document.write( "Plug value of the slope and point ( -5 , 4 ) in \n" ); document.write( "Y = m x + b \n" ); document.write( "4.00 = 5/2 + b \n" ); document.write( "b= 4 - 5/2 \n" ); document.write( "b= 3/ 2 \n" ); document.write( "So the equation will be \n" ); document.write( "Y = - 1/2 x + 3/2 \n" ); document.write( " \n" ); document.write( "EQUATION OF LINE PERPENDICULAR TO THIS LINE \n" ); document.write( "Find the slope of this line \n" ); document.write( " \n" ); document.write( "1 y = -1/2 x + 3/2 \n" ); document.write( "Divide by 1 \n" ); document.write( " y = -1/2 x + 3/2 \n" ); document.write( "Compare this equation with y=mx+b \n" ); document.write( "slope m = -1/2 \n" ); document.write( " \n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal \n" ); document.write( "m1*m2=-1 \n" ); document.write( "The slope of the required line will be 2 \n" ); document.write( " \n" ); document.write( "m= 2 ,point ( -8 , -8 ) \n" ); document.write( "Find b by plugging the values of m & the point in \n" ); document.write( "y=mx+b \n" ); document.write( "-8 = -16.00 + b \n" ); document.write( "b= 8 \n" ); document.write( "m= 2 \n" ); document.write( "The required equation is y = 2 x + 8 \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |