document.write( "Question 500013: james is twice as old as his friend peter. peter is 5 years older than alice right now. in 5 years, james will be three times as old as alice. how old is peter now? \n" ); document.write( "
Algebra.Com's Answer #338013 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Present age of James = j
\n" ); document.write( "Present age of Peter = p
\n" ); document.write( "Present age of Alice = a\r
\n" ); document.write( "\n" ); document.write( "James is twice as old as his friend peter
\n" ); document.write( "j=2p ..........(1)\r
\n" ); document.write( "\n" ); document.write( "Peter is 5 years older than Alice
\n" ); document.write( "p=a+5..........(2)\r
\n" ); document.write( "\n" ); document.write( "In 5 years, James will be three times as old as Alice
\n" ); document.write( "j+5=3(a+5)
\n" ); document.write( "j+5=3a+15
\n" ); document.write( "j=3a+15-5
\n" ); document.write( "j=3a+10......(3)\r
\n" ); document.write( "\n" ); document.write( "Put the value of j from (1) in (3)
\n" ); document.write( "j=3a+10
\n" ); document.write( "2p=3a+10 .......(4)
\n" ); document.write( "Multiply (2) by -3 and add to (4)
\n" ); document.write( "p=a+5..........(2)\r
\n" ); document.write( "\n" ); document.write( "-3p=-3a-15
\n" ); document.write( "+2p=3a+10
\n" ); document.write( "----------------
\n" ); document.write( "-p=-5
\n" ); document.write( "Multiply by (-1) both sides of the above equation
\n" ); document.write( "(-1)-p=-5(-1)
\n" ); document.write( "p=5\r
\n" ); document.write( "\n" ); document.write( "Peter is 5 years old
\n" ); document.write( "Put the value of p in (1)
\n" ); document.write( "j=2p
\n" ); document.write( "j=2*5
\n" ); document.write( "j=10
\n" ); document.write( "James is 10 years old
\n" ); document.write( "Put the value of p in (2)
\n" ); document.write( "p=a+5
\n" ); document.write( "5=a+5
\n" ); document.write( "5-5=a
\n" ); document.write( "a=0
\n" ); document.write( "Alice is 0 years old !!!!! \r
\n" ); document.write( "\n" ); document.write( "
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