document.write( "Question 500051: Mrs. Carter invested a sum of money at 4%. she invested a second sum, $250 more than the first sum, at 6%. If the total annual income was $90, how much did she invest at each amont? \n" ); document.write( "
Algebra.Com's Answer #337968 by mananth(16946)![]() ![]() You can put this solution on YOUR website! X------------4% \n" ); document.write( "x+250 -------6% \n" ); document.write( "Interest from both =90\r \n" ); document.write( "\n" ); document.write( "0.04x+0.06(x+250)= 90 \n" ); document.write( "0.04x+0.06x+15=90 \n" ); document.write( "0.1x=90-15 \n" ); document.write( "0.1x=75 \n" ); document.write( "x=750\r \n" ); document.write( "\n" ); document.write( "$750 @ 4% \n" ); document.write( "$1000 @ 6% \n" ); document.write( " |