document.write( "Question 500051: Mrs. Carter invested a sum of money at 4%. she invested a second sum, $250 more than the first sum, at 6%. If the total annual income was $90, how much did she invest at each amont? \n" ); document.write( "
Algebra.Com's Answer #337968 by mananth(16946)\"\" \"About 
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X------------4%
\n" ); document.write( "x+250 -------6%
\n" ); document.write( "Interest from both =90\r
\n" ); document.write( "\n" ); document.write( "0.04x+0.06(x+250)= 90
\n" ); document.write( "0.04x+0.06x+15=90
\n" ); document.write( "0.1x=90-15
\n" ); document.write( "0.1x=75
\n" ); document.write( "x=750\r
\n" ); document.write( "\n" ); document.write( "$750 @ 4%
\n" ); document.write( "$1000 @ 6%
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