document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=500050>Question 500050</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A radiator contains 15 quarts of fluid, 40% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #337966 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=337966\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 	percent	----------------	quantity									<BR>\n" );
document.write( "Antifreeze I	40	----------------			5	quarts						<BR>\n" );
document.write( "Antifreeze II	100	----------------			x	quarts						<BR>\n" );
document.write( "Mixture	60	----------------	15	+	x	quarts						<BR>\n" );
document.write( "												<BR>\n" );
document.write( "40	*	5	+	100	x	=	60	(	15	+	x	)<BR>\n" );
document.write( "200	+	100	x	=	900	+	60	x				<BR>\n" );
document.write( "100	x	+	-60	x	=	900	-	-200				<BR>\n" );
document.write( "40	x	=	700									<BR>\n" );
document.write( "/	40											<BR>\n" );
document.write( "x	=	17.5										<BR>\n" );
document.write( "		17.5	quarts		of	100	%	Antifreeze II<BR>\n" );
document.write( "So 17.5 quarts has to be drained				<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );