document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=500028>Question 500028</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, my Algebra homework is becoming very difficult for me. May you please help me solve the following problem? <BR>\n" );
document.write( "3/n - 1/4 = 1/12 - 5/3<BR>\n" );
document.write( "Three over n - one fourth = one over twelve - five over three. <BR>\n" );
document.write( "If you have a little extra time may you please, explain the steps on how to do it? Well, thank you for helping me. I really do appreciate it(: </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #337958 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=337958\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3/n-1/4=1/12-5/3<BR>\n" );
document.write( "3/n=1/12-5/3+1/4<BR>\n" );
document.write( "3/n=1/12-20/12+3/12<BR>\n" );
document.write( "3/n=-16/12<BR>\n" );
document.write( "n=-16/12*3/1<BR>\n" );
document.write( "n=48/12<BR>\n" );
document.write( "n=4<BR>\n" );
document.write( "Don't for get about common denominators. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );