document.write( "Question 499977: How much pure silver must be alloyed with a 36% silver alloy to obtain 100 gm of a 52% alloy? \n" ); document.write( "
Algebra.Com's Answer #337934 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Do mixtures and solutions like this: \n" ); document.write( "------ \n" ); document.write( "how many liters of a 70% acid solution must be mixed with a 15% acid solution to get 385L of a 60% acid solution? \n" ); document.write( "------------------- \n" ); document.write( "s = amount of 70% \n" ); document.write( "f = amount of 15% \n" ); document.write( "------- \n" ); document.write( "s + f = 385 (total solution) \n" ); document.write( "0.7s + 0.15f = 0.6*385 (total acid) \n" ); document.write( "------- \n" ); document.write( "f = 385 - s \n" ); document.write( "Sub for f in 2nd equation \n" ); document.write( "0.7s + 0.15(385-s) = 231 \n" ); document.write( "70s + 5775 - 15s = 23100 \n" ); document.write( "55s = 17325 \n" ); document.write( "s = 315 liters of 70% \n" ); document.write( "------------ \n" ); document.write( "f = 70 liters of 15% \n" ); document.write( " |