document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=499851>Question 499851</A>: <I><SPAN STYLE=\"word-break: break-all;\"> is this the same as the section as<BR>\n" );
document.write( "Applications of Linear Systems?\r<BR>\n" );
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document.write( "Ex: A motel clerk counts his $1 and $10 bills at the end of the day. He finds that he has a total of 74 bills having a combined monetary value of $326. Find the number of bills of each denomination that he has.<BR>\n" );
document.write( "let x= the number of $1 bills the clerk has, and y= the number of $10 bills he has <BR>\n" );
document.write( "He has 74 bills altogether, so one equation is x+y=74. To find the second equation, the dollar amount in $1 bills plus the dollar amount in $10 bills is $326, so 1x+10y=326. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #337894 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=337894\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=74 y=74-x<BR>\n" );
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document.write( "x+10y=326<BR>\n" );
document.write( "x+10(74-x)=326<BR>\n" );
document.write( "x+740-10x=326<BR>\n" );
document.write( "-9x=-414<BR>\n" );
document.write( "x=-414/-9<BR>\n" );
document.write( "x=46<BR>\n" );
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document.write( "y=74-46<BR>\n" );
document.write( "y=28 </SPAN>\n" );
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