document.write( "Question 499869: I dont understand how to write an equation of the line that passes through (-2,1) and is perpindicular to y=1/2x+1.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #337883 by oberobic(2304)\"\" \"About 
You can put this solution on YOUR website!
y = 1/2x + 1 is an equation in y = mx + b form.
\n" ); document.write( "This form is known as \"slope-intercept\" because m is the slope and b is the y-intercept.
\n" ); document.write( ".
\n" ); document.write( "The slope of a line perpendicular to this line will have slope = inverse reciprocal.
\n" ); document.write( "The inverse reciprocal of 1/2 is -2.
\n" ); document.write( ".
\n" ); document.write( "So the line we're looking for is:
\n" ); document.write( "y = -2x + b
\n" ); document.write( ".
\n" ); document.write( "It will run from the upper left corner of the graph to the lower right corner.
\n" ); document.write( "The y value will be decreasing as the x value is increasing.
\n" ); document.write( ".
\n" ); document.write( "There are infinitely many lines with slope -2.
\n" ); document.write( "But only one line with slope = -2 will go through the point (-2,1).
\n" ); document.write( ".
\n" ); document.write( "Notice that (-2,1) means that when x=-2, y=1.
\n" ); document.write( ".
\n" ); document.write( "We can plug that into the equation and find 'b'.
\n" ); document.write( ".
\n" ); document.write( "y = -2x + b
\n" ); document.write( "1 = -2(-2) + b
\n" ); document.write( "1 = 4 + b
\n" ); document.write( "subtract 4 from both sides
\n" ); document.write( "-3 = b
\n" ); document.write( "so
\n" ); document.write( "b = -3
\n" ); document.write( ".
\n" ); document.write( "That means the equation you need to find is:
\n" ); document.write( "y = -2x -3
\n" ); document.write( ".
\n" ); document.write( "The following graphs show the two lines.
\n" ); document.write( ".
\n" ); document.write( "\"graph%28500%2C500%2C-5%2C5%2C-5%2C5%2C1%2F2%2Ax%2B1%2C-2%2Ax-3%29\"
\n" ); document.write( ".
\n" ); document.write( "Done.
\n" ); document.write( "
\n" );