document.write( "Question 499737:
\n" ); document.write( "2b^4+14b^3-16b-112\r
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Algebra.Com's Answer #337863 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming you want to factor this.\r
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\n" ); document.write( "\n" ); document.write( "\"2b%5E4%2B14b%5E3-16b-112\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%282b%5E4%2B14b%5E3%29%2B%28-16b-112%29\" Group the terms in two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"2b%5E3%28b%2B7%29-16%28b%2B7%29\" Factor out the GCF \"2b%5E3\" out of the first group. Factor out the GCF \"-16\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%282b%5E3-16%29%28b%2B7%29\" Since we have the common term \"b%2B7\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"2%28b%5E3-8%29%28b%2B7%29\" Factor out the GCF 2 from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"2%28b-2%29%28b%5E2%2B2b%2B4%29%28b%2B7%29\" Factor \"b%5E3-8\" using the difference of cubes formula.\r
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\n" ); document.write( "\n" ); document.write( "So \"2b%5E4%2B14b%5E3-16b-112\" factors to \"2%28b-2%29%28b%5E2%2B2b%2B4%29%28b%2B7%29\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"2b%5E4%2B14b%5E3-16b-112=2%28b-2%29%28b%5E2%2B2b%2B4%29%28b%2B7%29\"
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