document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=499622>Question 499622</A>: <I><SPAN STYLE=\"word-break: break-all;\"> K over 7 =10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #337833 by </B><A HREF=/tutors/aboutme.mpl?userid=Flannery><B>Flannery(124)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Flannery><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Flannery><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=337833\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Remember another name for 10 is 10/1.<BR>\n" );
document.write( "K/7=10/1<BR>\n" );
document.write( "Cross multiply to get an equation.<BR>\n" );
document.write( "1K=70 (K=70)<BR>\n" );
document.write( "It's a ratio, and cross multiplication, also known as the rule of three, will always work. </SPAN>\n" );
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