document.write( "Question 499673: 12x suqared plus 82x-14=0\r
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Algebra.Com's Answer #337822 by Earlsdon(6294)\"\" \"About 
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\"12x%5E2%2B82x-14+=+0\" You can solve this by factoring.
\n" ); document.write( "\"%2812x-2%29%28x%2B7%29+=+0\" Apply the \"zero product\" rule.
\n" ); document.write( "\"12x-2+=+0\" or \"x%2B7+=+0\" then...
\n" ); document.write( "\"12x+=+2\" so \"x+=+1%2F6\" or
\n" ); document.write( "\"x%2B7+=+0\" so \"x+=+-7\"
\n" ); document.write( "The roots are:
\n" ); document.write( "\"x+=+1%2F6\" and \"x+=+-7\"
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