document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=50605>Question 50605</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the surface area of a right circular cylinder is 12 Pi, and the height is 1,what is its radius? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #33777 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=33777\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the surface area of a right circular cylinder is 12 Pi, and the height is 1,what is its radius?<BR>\n" );
document.write( "s.a=2pi*r^2+2pi*r*h=12pi<BR>\n" );
document.write( "12=2r^2+2r*1<BR>\n" );
document.write( "r^2+r-6=0<BR>\n" );
document.write( "(r+3)(r-2)=0<BR>\n" );
document.write( "r=2  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );