document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=499532>Question 499532</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bus has to cover 72 Km in 1hr 30 minutes. However for the first 36 Km, speed was 54 Km/hr. At what speed must it travel for the rest of   distance in order to complete the journey in time.	<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #337759 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=337759\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 72 km ------------ 3/2 hour\r<BR>\n" );
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document.write( "First part -----36 km----------- 54 km/hr<BR>\n" );
document.write( "time = 36/54 = 2/3 hours\r<BR>\n" );
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document.write( "Balance time to reach on time = 3/2-2/3= 5/6 hours\r<BR>\n" );
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document.write( "Balance distance = 72-36 = 36 km\r<BR>\n" );
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document.write( "Speed = distance/time<BR>\n" );
document.write( "speed = 36/(5/6)<BR>\n" );
document.write( "speed = 36* 6/5<BR>\n" );
document.write( "speed = 43.2 km/h second part\r<BR>\n" );
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