document.write( "Question 499518: A freight train, traveling at an average rate of 30 mi/h, leaves san francisco for Los Angeles. 5 hours later, a passenger train, traveling at an average rate of 55 mi/hr, leaves San Francisco for Los Angeles. How far are the trains from San Francisco when the passenger train passes the freight train? \n" ); document.write( "
Algebra.Com's Answer #337756 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Freight train 30 mph \n" ); document.write( "Passenger train 55 mph \n" ); document.write( "Freight train 02:00 \n" ); document.write( "Passenger train 07:00 \n" ); document.write( "Difference in time= 05:00 => 5 hours \n" ); document.write( "Freight train will have covered 150 miles before Passenger train starts from frisco \n" ); document.write( "catch up distance= 150 miles \n" ); document.write( "catch up speed = 55 -30 mph \n" ); document.write( "catch up speed = 25 mph \n" ); document.write( "Catchup time = catchup distance/catch up speed \n" ); document.write( "catch up time= 150 / 25 \n" ); document.write( "catch up time= 6 hours \r \n" ); document.write( "\n" ); document.write( " trains will be 11*30= 330 km \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |