document.write( "Question 499494: Use the given information to find each value.
\n" ); document.write( "sint=(-12/13) π < t < 3π/2\r
\n" ); document.write( "\n" ); document.write( "(a) cos 2t\r
\n" ); document.write( "\n" ); document.write( "(b) sin 2t\r
\n" ); document.write( "\n" ); document.write( "(c) cos(t/2)\r
\n" ); document.write( "\n" ); document.write( "(d) sin(t/2)
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Algebra.Com's Answer #337745 by lwsshak3(11628)\"\" \"About 
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Use the given information to find each value.
\n" ); document.write( "sint=(-12/13) π < t < 3π/2
\n" ); document.write( "(a) cos 2t
\n" ); document.write( "(b) sin 2t
\n" ); document.write( "(c) cos(t/2)
\n" ); document.write( "(d) sin(t/2)
\n" ); document.write( "**
\n" ); document.write( "sint=(-12/13)
\n" ); document.write( "You are working with 5-12-13 right triangle in quadrant III where sin and cos are<0
\n" ); document.write( "cost=(-5/13)
\n" ); document.write( "..
\n" ); document.write( "(a) cos 2t=cos^2t-sin^2t=(-5/13)^2-(-12/13)^2=0.1479-0.8521=-0.7042
\n" ); document.write( "(b) sin 2t=2sintcost=2(-12/13)(-5/13)=0.7101
\n" ); document.write( "(c) cos(t/2)=±√((1+cost)/2)=-√((1-5/13)/2)=-√0.3077=-0.5547 (choose negative root because t/2 is in quadrant II where cos is <0
\n" ); document.write( "(d) sin(t/2)=±√((1-cost)/2)=√((1+5/13)/2)=√0.6923=0.8320 (choose positive root because t/2 is in quadrant II where sin is >0
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