document.write( "Question 499423: jennifer is 6 years older than sue. in 4 years, she will be twice as old as sue was 5 years ago. find their ages now. \n" ); document.write( "
Algebra.Com's Answer #337679 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! J = Jennifer's age \n" ); document.write( "S = Sue's age \n" ); document.write( "J = S+6 \n" ); document.write( ". \n" ); document.write( "In 4 years... \n" ); document.write( "J+4 \n" ); document.write( ". \n" ); document.write( "J will be twice as old as S was 5 years ago \n" ); document.write( "J+4 = 2(S-5) \n" ); document.write( "J = 2S - 10 - 4 \n" ); document.write( "J = 2S -14 \n" ); document.write( ". \n" ); document.write( "Substitute \n" ); document.write( ".\r \n" ); document.write( "\n" ); document.write( "S+6 = 2S-14 \n" ); document.write( "-S = -20 \n" ); document.write( "S = 20 \n" ); document.write( "J = 20+6 \n" ); document.write( "J = 26 \n" ); document.write( ". \n" ); document.write( "Check. \n" ); document.write( "In 4 years: \n" ); document.write( "J+4 = 26 + 4 = 30 \n" ); document.write( "... \n" ); document.write( "Jennifer will be twice as old as Sue was 5 years ago. \n" ); document.write( "5 years ago Sue was 20-5 = 15 years old \n" ); document.write( "2 * 15 = 30 \n" ); document.write( "... \n" ); document.write( "Correct. \n" ); document.write( ". \n" ); document.write( "Answer: \n" ); document.write( "Jennifer is 26, and Sue is 20. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |