document.write( "Question 499339: what is the mass of a 1 cup of a 12% alcohol-water solution?
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document.write( "10% solution is 0.98569
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document.write( "15% is 0.98024 \n" );
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Algebra.Com's Answer #337621 by chessace(471)![]() ![]() You can put this solution on YOUR website! Let DA = density (mass/vol) of Alcohol; DW = density of water \n" ); document.write( "Mass (density * volume): 0.1*DA + 0.9*DW = 0.98569 \n" ); document.write( "0.15*DA + 0.85*DW = 0.98024 \n" ); document.write( "0.12*DA + 0.88*DW = x \n" ); document.write( "3*DA + 27*DW = 30*0.98569 \n" ); document.write( "3*DA + 17*DW = 20*0.98024 \n" ); document.write( "10DW = 29.5707 - 19.6048 = 9.9659 \n" ); document.write( "DW = 0.99659 \n" ); document.write( "DA = 10 * (0.98569 - (0.9 * 0.99659)) \n" ); document.write( "DA = 10 * (0.98569 - 0.896931) \n" ); document.write( "DA = 0.88759 \n" ); document.write( "x = 0.12 * 0.88759 + 0.88 * 0.99659 \n" ); document.write( "x = 0.1065108 + 0.8769992 \n" ); document.write( "x = 0.98351 \n" ); document.write( "Note that this is between the stronger and weaker solutions, and proportional so, thus the simpler approach would be weighted average: \n" ); document.write( "x = (3 * 0.98569 + 2 * 0.98024) / 5 \n" ); document.write( " \n" ); document.write( " |