document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=499374>Question 499374</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the domain of 1/sqrt(3x+8) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #337620 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=337620\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/sqrt(3x+8)<BR>\n" );
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document.write( "The domain is affected by the square root function.<BR>\n" );
document.write( "We should assume we are limited to the real numbers, so the value of 3x+8 cannot be negative.<BR>\n" );
document.write( "Also, since the expression is in a denominator it cannot = 0.<BR>\n" );
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document.write( "x = -8/3 would result 0, so that cannot be allowed.<BR>\n" );
document.write( "x < -8/3 would result in a negative value, so that cannot be allowed.<BR>\n" );
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document.write( "So, the domain of x is all real x > -8/3.<BR>\n" );
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document.write( "Done. </SPAN>\n" );
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