document.write( "Question 50689: 1.9/3+3a/4=13/3
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Algebra.Com's Answer #33754 by AnlytcPhil(1806) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "      9/3 + 3a/4 = 13/3\r\n" );
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document.write( "The LCD of the denominators 3, 4, and 3 is 12. So\r\n" );
document.write( "multiply every term by 12·\r\n" );
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document.write( "12·9/3 + 12·3a/4 = 12·13/3\r\n" );
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document.write( "         36 + 9a = 52\r\n" );
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document.write( "Solve that and get a = 16/9\r\n" );
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document.write( "2.\r\n" );
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document.write( "         5x - 2/3 = 8 - 3x/5\r\n" );
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document.write( "The LCD of the denominators 3 and 5 is 15. So\r\n" );
document.write( "multiply every term by 15·\r\n" );
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document.write( "   15·5x - 15·2/3 = 15·8 - 15·3x/5\r\n" );
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document.write( "         75x - 10 = 120 - 9x\r\n" );
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document.write( "Solve that and get x = 65/42\r\n" );
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document.write( "3.\r\n" );
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document.write( "         b - 2/b + 4 = b + 1/b + 10\r\n" );
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document.write( "The LCD of the denominators b and b is b. So\r\n" );
document.write( "multiply every term by b·\r\n" );
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document.write( "   b·b - b·2/b + b·4 = b·b + b·1/b + b·10\r\n" );
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document.write( "         b² - 2 + 4b = b² + 1 + 10b\r\n" );
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document.write( "Solve that and get b = -1/2\r\n" );
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document.write( "4.\r\n" );
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document.write( "         5y - 1/2 - 3y + 5 = 7y + 13/6\r\n" );
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document.write( "I'll let you do that one by yourself. Answer = 7/15\r\n" );
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document.write( "Edwin

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