document.write( "Question 499272: the length of a rectangle is 10 units longer than its width. if the total perimeter of the rectangle is 44 units, what is the width? \n" ); document.write( "
Algebra.Com's Answer #337523 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! P = perimeter \n" ); document.write( "L = length \n" ); document.write( "W = width \n" ); document.write( "P = 2L + 2W = 2(L+W) \n" ); document.write( "P = 44 \n" ); document.write( ". \n" ); document.write( "L = W+10 \n" ); document.write( ". \n" ); document.write( "Substitute \n" ); document.write( ". \n" ); document.write( "2(W+10) + 2W = 44 \n" ); document.write( "2W + 20 + 2W = 44 \n" ); document.write( "4W = 24 \n" ); document.write( "W = 6 \n" ); document.write( ". \n" ); document.write( "L = W+10 \n" ); document.write( "L = 6+10 \n" ); document.write( "L = 16 \n" ); document.write( ". \n" ); document.write( "Check your work! \n" ); document.write( "2L = 32 \n" ); document.write( "2W = 12 \n" ); document.write( "32+12 = P = 44 \n" ); document.write( "Correct. \n" ); document.write( ". \n" ); document.write( "Re-read the question to make sure you answer it. \n" ); document.write( "The width is 6. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |