document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=499219>Question 499219</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A water tank can be emptied by using one pump for 4 hours. A second, smaller pump can empty the tank in 11 hours. If the larger pump is started at 1:00 P.M., at what time should the smaller pump be started so that the tank will be emptied at 4:00 P.M.? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #337476 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=337476\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A water tank can be emptied by using one pump for 4 hours. A second, smaller pump can empty the tank in 11 hours. If the larger pump is started at 1:00 P.M., at what time should the smaller pump be started so that the tank will be emptied at 4:00 P.M.?<BR>\n" );
document.write( "total time first pump is running:3 hours<BR>\n" );
document.write( "Let x = time second pump is running<BR>\n" );
document.write( "then<BR>\n" );
document.write( "3(1/4) + x(1/11) = 1<BR>\n" );
document.write( "multiply both sides by 44:<BR>\n" );
document.write( "3(11) + x(4) = 44<BR>\n" );
document.write( "33 + 4x = 44<BR>\n" );
document.write( "4x = 11<BR>\n" );
document.write( "x = 11/4<BR>\n" );
document.write( "x = 2.75 hours<BR>\n" );
document.write( "or<BR>\n" );
document.write( "x = 2 and 3/4 hours<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Answer: 1:15 pm<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );