document.write( "Question 499201: determine the smallest 6 digit number which is exactly divisible by 8,15,and21
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Algebra.Com's Answer #337465 by oberobic(2304)\"\" \"About 
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What are the factors of 8?
\n" ); document.write( "1, 2, 4
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\n" ); document.write( "What are the factors of 15?
\n" ); document.write( "1, 3, 5
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\n" ); document.write( "What are the factors of 21?
\n" ); document.write( "1, 3, 7
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\n" ); document.write( "The domain set is: {1, 2, 4, 3, 5, 7}
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\n" ); document.write( "What is the least common multiple that is equal to or greater than 21 (the largest number)?
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\n" ); document.write( "1*2*4*3*5*7 = 840
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\n" ); document.write( "840/8 = 105
\n" ); document.write( "840/15 = 56
\n" ); document.write( "840/21 = 40
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\n" ); document.write( "So, 840 is looking good!
\n" ); document.write( "We can check 420, but we'll find it does not work for 8.
\n" ); document.write( "420/8 is not an integer solution.
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\n" ); document.write( "But what does the question ask? The smallest 6-digit number that is exactly divisible by 8, 15, and 21.
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\n" ); document.write( "How about 840,000?
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\n" ); document.write( "840,000/8 = 105,000
\n" ); document.write( "840,000/15 = 56,000
\n" ); document.write( "840,000/21 = 40,000
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\n" ); document.write( "That works, but is it the smallest 6-digit number?
\n" ); document.write( "Not likely.
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\n" ); document.write( "Looking back, 8*15*21*x, where x is an integer, will always be divisible exactly by 8, 15 & 21.
\n" ); document.write( "We want to find an x such that the product is > 100,000 by the smallest margin.
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\n" ); document.write( "8*15*21=2520
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\n" ); document.write( "2520x >= 100,000
\n" ); document.write( "x >= 39.6824397
\n" ); document.write( "The next integer is 40.
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\n" ); document.write( "40*2520 = 100,800
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\n" ); document.write( "100,800/8 = 12,600
\n" ); document.write( "100,800/15 = 6,720
\n" ); document.write( "100,800/21 = 4,800
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\n" ); document.write( "The smallest 6-digit number (that is, a number >= 100,000) that is exactly divisible by 8, 15, and 21 is 100,800.
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\n" ); document.write( "Done.
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