document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=498997>Question 498997</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given the numbers 1 - 9; arrange them so that the sum of two 3-digit numbers equals a 3 digit number  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #337386 by </B><A HREF=/tutors/aboutme.mpl?userid=chessace><B>chessace(471)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chessace><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chessace><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=337386\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Cool problem!<BR>\n" );
document.write( "Can't be done!<BR>\n" );
document.write( "Sum 1 to 9 is 45.<BR>\n" );
document.write( "The sum of all the digits of the 1st two 3 digit numbers + possible carry= <BR>\n" );
document.write( "sum of 3 \"answer\" digits.<BR>\n" );
document.write( "If there is no carry, these 2 \"equal\" sums add to an even number, not 45.<BR>\n" );
document.write( "So there must be a carry.<BR>\n" );
document.write( "And the \"answer\" digits must sum to 23.<BR>\n" );
document.write( "Only way is 9 8 6 and to get a carry, 9 would have to be on top too.<BR>\n" );
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