document.write( "Question 50655: 1/(2*x-6)+2/(3*x-9)=7/(x^2-3*x)\r
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Algebra.Com's Answer #33738 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
This is a fractional equation. Start by factoring the denominators so you can find the LCD for the problem.
\n" ); document.write( "\"1%2F%282%28x-3%29%29+%2B+2%2F%283%28x-3%29%29+=+7%2F%28x%28x-3%29%29+\"\r
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\n" ); document.write( "\n" ); document.write( "The LCD = 6x(x-3), so multiply both sides of the equation by the LCD. It's ugly at first, but in the first step all the fractions divide out!
\n" ); document.write( "\"1%2F%282%28x-3%29%29+%2B+2%2F%283%28x-3%29%29+=+7%2F%28x%28x-3%29%29+\"
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\n" ); document.write( "\n" ); document.write( "After all the denominator factors divide out, this is what is left:
\n" ); document.write( "\"3x+%2B+4x+=+42\"
\n" ); document.write( "\"7x+=+42\"
\n" ); document.write( "\"x+=+6\"\r
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\n" ); document.write( "\n" ); document.write( "One more step: Check each denominator, and make sure that x= 6 doesn't make any denominators zero. Also, you can check the answer by substituting x= 6 into the original equation (if you want to go to some trouble).\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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