document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=498572>Question 498572</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the perimeter is 100 meters and a the length is 14m more than the width what is the length and the width? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #337378 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=337378\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = w<BR>\n" );
document.write( "x + 14 = L<BR>\n" );
document.write( "2x + 2x + 28 = 100<BR>\n" );
document.write( "4x = 72<BR>\n" );
document.write( "x = 18 meters the width.<BR>\n" );
document.write( "32 = meters the length<BR>\n" );
document.write( "2(18) + 2(32) = 100 meters<BR>\n" );
document.write( "Cleomenius. </SPAN>\n" );
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