document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=50654>Question 50654</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I have a question that is assume log4=.6021 determine log1\16.  I know I can do this on the calculator and find log 1/16 is -1.2041, but that gives me no understanding of the problem.  Is there a way to do working out to come to the solution??? thanks very much. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #33736 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=33736\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given log 4 = .6021, notice that 1/16 is actually <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%5E-2 ALIGN=MIDDLE  ALT=\"4%5E-2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "So, log 1/16<BR>\n" );
document.write( "= log 4^-2<BR>\n" );
document.write( "= -2* log 4<BR>\n" );
document.write( "=-2(.6021)<BR>\n" );
document.write( "=-1.2042\r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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