document.write( "Question 498947: A principal of $6500 is invested in an account paying an annual rate of 6%. Find the amount in the account after 6 years if the account compounded semiannually, quarterly, and monthly. \n" ); document.write( "
Algebra.Com's Answer #337353 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
your equation is:
\n" ); document.write( "f = p * (1 + (i/c))^(n*c)
\n" ); document.write( "f = future value
\n" ); document.write( "p = present value
\n" ); document.write( "i = annual interest rate
\n" ); document.write( "c = number of compound intervals per year
\n" ); document.write( "n = number of years.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "your principal is 6500.
\n" ); document.write( "your annual interest rate is 6%
\n" ); document.write( "you want to find the amount in the account after 6 years.
\n" ); document.write( "money is compounded semi-annually, quarterly, and monthly.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "money is compounded semi-annually:
\n" ); document.write( "p = 6500
\n" ); document.write( "i = .06 (annual interest rate percent divided by 100%).
\n" ); document.write( "n = 6
\n" ); document.write( "c = 2
\n" ); document.write( "i/c = .06/2 = .03
\n" ); document.write( "n*c = 6*2 = 12
\n" ); document.write( "formula becomes:
\n" ); document.write( "f = 6500 * (1.03)^12 = 9267.45\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "money is compounded quarterly:
\n" ); document.write( "p = 6500
\n" ); document.write( "i = .06 (annual interest rate percent divided by 100%).
\n" ); document.write( "n = 6
\n" ); document.write( "c = 4
\n" ); document.write( "i/c = .06/4 = .015
\n" ); document.write( "n*c = 6*4 = 24
\n" ); document.write( "formula becomes:
\n" ); document.write( "f = 6500 * (1.015)^24 = 9291.77\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "money is compounded monthly:
\n" ); document.write( "p = 6500
\n" ); document.write( "i = .06 (annual interest rate percent divided by 100%).
\n" ); document.write( "n = 6
\n" ); document.write( "c = 12
\n" ); document.write( "i/c = .06/12 = .005
\n" ); document.write( "n*c = 6*12 = 72
\n" ); document.write( "formula becomes:
\n" ); document.write( "f = 6500 * (1.005)^72 = 9308.28781\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the more compounding intervals per year, the more money you make.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );