document.write( "Question 498947: A principal of $6500 is invested in an account paying an annual rate of 6%. Find the amount in the account after 6 years if the account compounded semiannually, quarterly, and monthly. \n" ); document.write( "
Algebra.Com's Answer #337353 by Theo(13342)![]() ![]() You can put this solution on YOUR website! your equation is: \n" ); document.write( "f = p * (1 + (i/c))^(n*c) \n" ); document.write( "f = future value \n" ); document.write( "p = present value \n" ); document.write( "i = annual interest rate \n" ); document.write( "c = number of compound intervals per year \n" ); document.write( "n = number of years.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your principal is 6500. \n" ); document.write( "your annual interest rate is 6% \n" ); document.write( "you want to find the amount in the account after 6 years. \n" ); document.write( "money is compounded semi-annually, quarterly, and monthly.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "money is compounded semi-annually: \n" ); document.write( "p = 6500 \n" ); document.write( "i = .06 (annual interest rate percent divided by 100%). \n" ); document.write( "n = 6 \n" ); document.write( "c = 2 \n" ); document.write( "i/c = .06/2 = .03 \n" ); document.write( "n*c = 6*2 = 12 \n" ); document.write( "formula becomes: \n" ); document.write( "f = 6500 * (1.03)^12 = 9267.45\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "money is compounded quarterly: \n" ); document.write( "p = 6500 \n" ); document.write( "i = .06 (annual interest rate percent divided by 100%). \n" ); document.write( "n = 6 \n" ); document.write( "c = 4 \n" ); document.write( "i/c = .06/4 = .015 \n" ); document.write( "n*c = 6*4 = 24 \n" ); document.write( "formula becomes: \n" ); document.write( "f = 6500 * (1.015)^24 = 9291.77\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "money is compounded monthly: \n" ); document.write( "p = 6500 \n" ); document.write( "i = .06 (annual interest rate percent divided by 100%). \n" ); document.write( "n = 6 \n" ); document.write( "c = 12 \n" ); document.write( "i/c = .06/12 = .005 \n" ); document.write( "n*c = 6*12 = 72 \n" ); document.write( "formula becomes: \n" ); document.write( "f = 6500 * (1.005)^72 = 9308.28781\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the more compounding intervals per year, the more money you make.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |