document.write( "Question 499020: By increasing her usual speed by 25 kilometers per hour, a bus driver decreases the time on a 25-kilometer trip by 10 minutes. Find the usual speed.\r
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document.write( " The Vilas County News earns a profit of $20 per year for each of its 3,000 subscribers. Management projects that the profit per subscriber would increase by 1¢ for each additional subscriber over the current 3,000. How many total subscribers are needed to bring a total profit of $113,100?
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document.write( "Perform the operations and simplify. 1/x times x^2-15x all over x-14 \n" );
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Algebra.Com's Answer #337350 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! By increasing his usual speed by 25 kilometers per hour, a bus driver decreases the time on a 25-kilometer trip by 10 minutes. \n" ); document.write( " Find the usual speed. \n" ); document.write( ": \n" ); document.write( "Let s = his usual speed \n" ); document.write( "Change 10 min to 1/6 hr \n" ); document.write( "write a time equation; time = dist/speed \n" ); document.write( "Usual time - 10 min = faster time \n" ); document.write( " \n" ); document.write( "multiply by 6s(s+25), results \n" ); document.write( "6(s+25)*25 - s(s+25) = 6s*25 \n" ); document.write( "150(s+25) - s^2 - 25s = 150s \n" ); document.write( "150s + 3850 - s^2 - 25s = 150s \n" ); document.write( "Combine as a quadratic equation on the right \n" ); document.write( "0 = s^2 + 25s - 3750 \n" ); document.write( "Factors to \n" ); document.write( "(x-50)(x+75) = 0 \n" ); document.write( "Positive solution \n" ); document.write( "x = 50 mph is his usual speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "The Vilas County News earns a profit of $20 per year for each of its 3,000 subscribers. \n" ); document.write( "Management projects that the profit per subscriber would increase by 1¢ for each additional subscriber over the current 3,000. \n" ); document.write( " How many total subscribers are needed to bring a total profit of $113,100? \n" ); document.write( ": \n" ); document.write( "Find the present profit: 3000 * $20 = $60000 \n" ); document.write( "then: 113100 - 60000 = $53,100 increase in profits \n" ); document.write( "Let n = number of subscribers over 3000 to increase profit by 1 cent for each \n" ); document.write( ".01n = 53100 \n" ); document.write( "n = \n" ); document.write( "n = 5,310,000 additional subscribers, doesn't seem very realistic, does it! \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Perform the operations and simplify. \n" ); document.write( " \n" ); document.write( "------------ \n" ); document.write( " (x - 14) \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "------------ \n" ); document.write( " (x - 14) \n" ); document.write( ": \n" ); document.write( "Cancel the x and you are left with \n" ); document.write( " |