document.write( "Question 498994: Things did not quite go as planned. You invested $20,000, part of it in a stock that paid 12% annual interest. However, the rest of the money suffered a 5% loss. If the total annual income from both investments was $1890, how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #337344 by Theo(13342)\"\" \"About 
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x = amount in stock.
\n" ); document.write( "20,000 - x = the rest of it.
\n" ); document.write( "interest earned on x is .12x
\n" ); document.write( "money lost on 20,000 - x is .05(20,000-x)
\n" ); document.write( "total income from both investments is $1,890.
\n" ); document.write( "your income equation is:
\n" ); document.write( ".12x - .05(20,000 - x) = 1890
\n" ); document.write( "simplify to get:
\n" ); document.write( ".12x - .05*20,000 + .05x = 1890
\n" ); document.write( "combine like terms and simplify further to get:
\n" ); document.write( ".17x - 1000 = 1890
\n" ); document.write( "add 1000 to both sides of the equation to get:
\n" ); document.write( ".17x = 2890
\n" ); document.write( "divide both sides of the equation by .17 to get:
\n" ); document.write( "x = 2890/.17 = 17000.00
\n" ); document.write( "that's the amount that was invested earning 12%.
\n" ); document.write( "the income from that amount is equal to .12*17000 = 2040.
\n" ); document.write( "that least 3000 that was invested elsewhere.
\n" ); document.write( "the money that was lost was equal to 5% of that which made it equal to 150.
\n" ); document.write( "2040 - 150 = equals a net gain of 1890.
\n" ); document.write( "the value for x is confirmed as being good because that value, when substituted into the original problem statement showed that statement to be true.
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