document.write( "Question 499042: Hello! May you help me with this question?
\n" ); document.write( "If the hypotenuse of a right triangle is 10 and one leg is 5 radical 3, then the area if the triangle is...
\n" ); document.write( "(A) 5
\n" ); document.write( "(B) 25 radical 3
\n" ); document.write( "(C) 25
\n" ); document.write( "(D) 50 radical 3
\n" ); document.write( "(E) 12.5 radical 3\r
\n" ); document.write( "\n" ); document.write( "This is what i did to try to solve the problem. So according to Pythagorean theorem I did this formula a(squared)+b(squared)= c(squared). Since the hypotenuse is always c and one leg is 5 radical 3, this is what i did a(squared)+ 5 radical 3(squared)= 10(squared). which equals a(squared)+ 15= 100.
\n" ); document.write( "this can be simplified to a(squared)=85. so a is the square root of 85. since this is the height, and 5 radical 3 is the base i multiply radical 85 times 5 radical 3. which is 5 radical 255. then i divide this by 2 and get 2.5 radical 255. but this is not one of the choices. May you tell me what you got and how please? :) thank you\r
\n" ); document.write( "\n" ); document.write( " By, Nang Tun
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Algebra.Com's Answer #337315 by richard1234(7193)\"\" \"About 
You can put this solution on YOUR website!
You have to square 5sqrt(3). What you did was square (sqrt3) then multiply by 5.\r
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\n" ); document.write( "\n" ); document.write( "By the Pythagorean theorem, a would therefore be\r
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\n" ); document.write( "\n" ); document.write( "You can also find a by noting that this is a 30-60-90 triangle.\r
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\n" ); document.write( "\n" ); document.write( "The area of the triangle is 5(5sqrt(3))/2 = 12.5(sqrt3).
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