document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=498920>Question 498920</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary if their sum is 90degrees.  The larger angle measures three degrees less than twice the measure of a smaller angle.  If x represents the measure of the smaller angle and these two angles are complementary, find the measure of each angle.  \r<BR>\n" );
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document.write( "Not sure if this is what it would start of like:  x(2x-3)=90 or x+(2x-3)=90 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #337273 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=337273\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary if their sum is 90degrees.  The larger angle measures three degrees less than twice the measure of a smaller angle.  If x represents the measure of the smaller angle and these two angles are complementary, find the measure of each angle.<BR>\n" );
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document.write( "Let x = the smaller angle<BR>\n" );
document.write( "Then 90 - x = the larger angle<BR>\n" );
document.write( "Given: the larger angle is 3 less than twice the smaller<BR>\n" );
document.write( "90 - x = 2x - 3<BR>\n" );
document.write( "Solve for x:<BR>\n" );
document.write( "3x = 93<BR>\n" );
document.write( "x = 31<BR>\n" );
document.write( "So the smaller angle = 31 deg<BR>\n" );
document.write( "The larger angle = 90 - 29 = 59 deg </SPAN>\n" );
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