document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=498968>Question 498968</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor by grouping:  24c^3 + 116c^2 - 168c.  Here is what I have done so far:  The equation is in the correct order and the GCF of all 3 numbers is 4c  so I get:  4c(6c^2 + 29c - 42)  Now this is where I'm stuck...<BR>\n" );
document.write( "6c^2 + 29c - 42 = (3c + __)(2c - __)  \r<BR>\n" );
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document.write( "Now I use the F.O.I.L method to check my problem and it won't equal:<BR>\n" );
document.write( "3c * 2c = 6c^2<BR>\n" );
document.write( "-7 * 6 = -42<BR>\n" );
document.write( "but the rest won't give me the 29c, it gives me 4c.  So I think I missed something and can't figure it out!  Think I missed something in the beginning but really feel I didn't????  Please Help!  Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #337263 by </B><A HREF=/tutors/aboutme.mpl?userid=chessace><B>chessace(471)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chessace><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chessace><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=337263\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What you missed was 6=3*2 is not forced.<BR>\n" );
document.write( "I'll let you take it from there.<BR>\n" );
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