document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=498929>Question 498929</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist combines HCl acid solutions of 40%, 50%, and 25% to get 200 liters of a 32% HCl solution. If the chemist uses twice as much of the 25% HCl solution as of the 40% HCl solution, find how many liters of each kind he uses. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #337246 by </B><A HREF=/tutors/aboutme.mpl?userid=chessace><B>chessace(471)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chessace><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chessace><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=337246\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Translate:<BR>\n" );
document.write( "a+b+c=200<BR>\n" );
document.write( ".4a+.5b+.25c=.32*200<BR>\n" );
document.write( "c=2a<BR>\n" );
document.write( "Compute:<BR>\n" );
document.write( "b=200-3a<BR>\n" );
document.write( ".4a+.5(200-3a)+.25*2a=.32*200<BR>\n" );
document.write( "(.4-1.5+.5)a=200(.32-.5)<BR>\n" );
document.write( "-.6a=200*(-.18)<BR>\n" );
document.write( "a=200*.3= 60 liters<BR>\n" );
document.write( "c= 120 liters<BR>\n" );
document.write( "b= 20 liters\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );