document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=498898>Question 498898</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Okay, the gist of the math problem is.. A farmer wants to mix a bag containing 50% corn and another bag containing 90% corn to get a 30 lbs bag containing 80% corn.\r<BR>\n" );
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document.write( "What I have so far for the equation is.. 0.50x + 0.90x = ???<BR>\n" );
document.write( "I don't know how to 'plug-in' the other 0.80 and the weight of the bag.<BR>\n" );
document.write( "I hope this makes sense!! Thank you!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #337235 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=337235\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Try this!<BR>\n" );
document.write( "Let x = the number of pounds of the 50% corn.  Then the number of pounds of the 90% corn required to make 30 pounds of 80% corn will be (30-x) and, when added together (x+(30-x) = 30) you will get 30 pounds of corn. So we can write an equation to solve for x:<BR>\n" );
document.write( "0.5x+0.9(30-x) = 0.8(30) Simplify and solve for x.<BR>\n" );
document.write( "0.5x+27-0.9x = 24<BR>\n" );
document.write( "-0.4x+27 = 24<BR>\n" );
document.write( "-0.4x = -3<BR>\n" );
document.write( "x = 7.5<BR>\n" );
document.write( "The farmer will need to mix 7.5 pounds of the 50% corn with (30-7.5 = 22.5)pounds of the 90% corn to obtain 30 pounds of 80% corn. </SPAN>\n" );
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